Math.pow() method only works on the number primitive values, and not on the bigint primitive values. Therefore, to calculate the power of a bigint value, you can use the exponentiation operator (
// ES10+ const pow = (base, exponent) => base ** exponent; console.log(pow(2n, 10n)); // 1024n console.log(pow(12345679n, 2n)); // 152415789971041n console.log(pow(18014398509481982n, 2n)); // 324518553658426654725561982648324n
n" at the end of a number merely suggests that the number is a bigint primitive.
You cannot mix the number primitive and bigint primitive together as it will throw an error.
For example, mixing number and bigint together throws an error like the following:
// ES10+ const pow = (base, exponent) => base ** exponent; // TypeError: Cannot mix BigInt and other types, use explicit conversions console.log(pow(2n, 10));
That being said, you may use number primitives with the exponentiation operator (
**) as long as both, the base and the exponent, are of the same type:
// ES7+ // ... console.log(pow(2, 10)); // 1024
The minimum requirement of ES7 in this case is because the exponentiation operator was released with ES7.
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