How to Make All Properties of a TypeScript Type Required?

Learn how to create a new type from an existing one with all properties as required

To make all properties of an existing TypeScript type required, starting with TypeScript 2.8, you can simply use the Required utility type, which has the following syntax:

// TypeScript 2.8+

This would strip the ? modifiers from all properties of a type, making them all required.

For example, you can use the Required utility type in the following way:

// TypeScript 2.8+
interface Foo {
    bar?: string;
    baz?: number;
    qux?: boolean;

type RequiredFoo = Required<Foo>;

You could use this type in the following way:

const foo: RequiredFoo = { bar: 'abc', baz: 123, qux: false };

If any of the required types are missing, it will throw an error, like in the following case:

// TypeScript 2.8+
// Error: Property 'qux' is missing in type '{ bar: string; baz: number; }' but required in type 'Required<Foo>'.
const foo: RequiredFoo = { bar: 'abc', baz: 123 };

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