In Python, you can use the
int() method (with a base
8 as the second argument) to convert an octal string to its integer equivalent, for example, like so:
num = int('30071', 8) print(num) #=> 12345
This also works with octal strings that have the "
0o" (or "
0O") octal radix prefix:
# Python 2.6+ num = int('0o30071', 8) print(num) #=> 12345
# Python 2.6+ num = int('0O30071', 8) print(num) #=> 12345
Specifying an invalid octal number would raise the following error:
// ValueError: invalid literal for int() with base 8: '0x30071' int('0x30071', 8)
If the octal string has
0O) radix prefix, then you may also specify
0 as the second argument (i.e. the base) to the
int() method, which would make it infer the value:
# Python 2.6+ num = int('0o30071', 0) print(num) #=> 12345
This could be useful, for example, if a variable with a number can be of different types (such as binary, octal, hexadecimal, etc.).
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