How to Convert All Numbers in a JavaScript Array to Absolute Form?

Learn how to convert every number in an array of numbers to absolute form

In JavaScript, you can convert all numbers in an array of numbers to their absolute form, for example, in the following way:

// ES6+
const arr = [1234, -5678, 12.34, -56.78];
const newArr = arr.map((num) => Math.abs(num));

console.log(newArr); // [1234, 5678, 12.34, 56.78]

This works by calling the Math.abs() function on every element of the array using the Array.prototype.map() method.

You can rewrite the callback to Array.prototype.map() without arrow function to make it compatible with ES5.

If the array can potentially have bigint values as well, then Math.abs() will not work. In that case, you can do the following:

// ES10+
const arr = [-1234n, -5678, 12.34, -56.78];
const newArr = arr.map((num) => (num < 0n) ? -num : num);

console.log(newArr); // [1234n, 5678, 12.34, 56.78]

The examples above would create a new array with all numbers in the array in absolute form. You can achieve the same with a simple for loop as well:

const arr = [1234, -5678, 12.34, -56.78];
const newArr = [];

for (let i = 0; i < arr.length; i++) {
    newArr.push(Math.abs(arr[i]));
}

console.log(newArr); // [1234, 5678, 12.34, 56.78]

Or, you can use the following code if the array can have bigint values as well:

// ES10+
const arr = [-1234n, -5678, 12.34, -56.78];
const newArr = [];

for (let i = 0; i < arr.length; i++) {
    const num = arr[i];
    newArr.push((num < 0n) ? -num : num);
}

console.log(newArr); // [1234n, 5678, 12.34, 56.78]

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