# How to Convert All Numbers in a JavaScript Array to Absolute Form?

In JavaScript, you can convert all numbers in an array of numbers to their absolute form, for example, in the following way:

```// ES6+
const arr = [1234, -5678, 12.34, -56.78];
const newArr = arr.map((num) => Math.abs(num));

console.log(newArr); // [1234, 5678, 12.34, 56.78]
```

This works by calling the `Math.abs()` function on every element of the array using the `Array.prototype.map()` method.

You can rewrite the callback to `Array.prototype.map()` without arrow function to make it compatible with ES5.

If the array can potentially have bigint values as well, then `Math.abs()` will not work. In that case, you can do the following:

```// ES10+
const arr = [-1234n, -5678, 12.34, -56.78];
const newArr = arr.map((num) => (num < 0n) ? -num : num);

console.log(newArr); // [1234n, 5678, 12.34, 56.78]
```

The examples above would create a new array with all numbers in the array in absolute form. You can achieve the same with a simple `for` loop as well:

```const arr = [1234, -5678, 12.34, -56.78];
const newArr = [];

for (let i = 0; i < arr.length; i++) {
newArr.push(Math.abs(arr[i]));
}

console.log(newArr); // [1234, 5678, 12.34, 56.78]
```

Or, you can use the following code if the array can have bigint values as well:

```// ES10+
const arr = [-1234n, -5678, 12.34, -56.78];
const newArr = [];

for (let i = 0; i < arr.length; i++) {
const num = arr[i];
newArr.push((num < 0n) ? -num : num);
}

console.log(newArr); // [1234n, 5678, 12.34, 56.78]
```

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