In Python, you can use the `int()`

method (with a base `2`

as the second argument) to convert a binary string to its integer equivalent, for example, like so:

num = int('11000000111001', 2) print(num) #=> 12345

This also works with binary strings that have the "`0b`

" (or "`0B`

") binary radix prefix:

# Python 2.6+ num = int('0b11000000111001', 2) print(num) #=> 12345

# Python 2.6+ num = int('0B11000000111001', 2) print(num) #=> 12345

Specifying an invalid binary number would raise the following error:

```
// ValueError: invalid literal for int() with base 2: '0o11111'
int('0o11111', 2)
```

If the binary string *has* `0b`

(or `0B`

) radix prefix, then you may also specify `0`

as the second argument (i.e. the base) to the `int()`

method, which would make it *infer* the value:

# Python 2.6+ num = int('0b11000000111001', 0) print(num) #=> 12345

This could be useful, for example, if a variable with a number can be of different types (such as binary, octal, hexadecimal, etc.).

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